(x+5)^2/3=16

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Solution for (x+5)^2/3=16 equation:


x in (-oo:+oo)

((x+5)^2)/3 = 16 // - 16

((x+5)^2)/3-16 = 0

((x+5)^2)/3+(-16*3)/3 = 0

(x+5)^2-16*3 = 0

x^2+10*x-23 = 0

x^2+10*x-23 = 0

x^2+10*x-23 = 0

DELTA = 10^2-(-23*1*4)

DELTA = 192

DELTA > 0

x = (192^(1/2)-10)/(1*2) or x = (-192^(1/2)-10)/(1*2)

x = (8*3^(1/2)-10)/2 or x = (-8*3^(1/2)-10)/2

(x-((-8*3^(1/2)-10)/2))*(x-((8*3^(1/2)-10)/2)) = 0

((x-((-8*3^(1/2)-10)/2))*(x-((8*3^(1/2)-10)/2)))/3 = 0

((x-((-8*3^(1/2)-10)/2))*(x-((8*3^(1/2)-10)/2)))/3 = 0 // * 3

(x-((-8*3^(1/2)-10)/2))*(x-((8*3^(1/2)-10)/2)) = 0

( x-((-8*3^(1/2)-10)/2) )

x-((-8*3^(1/2)-10)/2) = 0 // + (-8*3^(1/2)-10)/2

x = (-8*3^(1/2)-10)/2

( x-((8*3^(1/2)-10)/2) )

x-((8*3^(1/2)-10)/2) = 0 // + (8*3^(1/2)-10)/2

x = (8*3^(1/2)-10)/2

x in { (-8*3^(1/2)-10)/2, (8*3^(1/2)-10)/2 }

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